Here is how to split a list into evenly sized parts in Python.

# Define a list to split
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

# Define the size of the parts
part_size = 3

# Use the range() function to create a list of the desired indices
indices = range(0, len(my_list), part_size)

# Use the enumerate() function to create pairs of (index, element) for each element in the list
pairs = enumerate(my_list)

# Use the zip() function to group the pairs of (index, element) by index
parts = [list(group) for index, group in groupby(pairs, lambda x: x[0] // part_size)]

# Print the resulting parts
print(parts) 

Copy & Run

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To split a list into evenly sized parts in Python, you can use the zip() function in combination with the enumerate() and range() functions. In this example, we define a list called my_list and a variable called part_size that specifies the size of the parts we want to split the list into. Then, we use the range() function to create a list of indices that we will use to split the list.

Next, we use the enumerate() function to create pairs of (index, element) for each element in the list. This allows us to keep track of the original position of each element in the list. Then, we use the zip() function to group the pairs of (index, element) by index. This creates a list of lists, where each inner list contains the elements that belong to the same part.

Finally, we print the resulting parts to the console. The output should be a list of lists, where each inner list contains the elements of the original list that belong to the same part.

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