Here is how to sort a dictionary by value in Python.

# Define a dictionary
my_dict = {
    "key1": "value1",
    "key2": "value2",
    "key3": "value3"
}

# Sort the dictionary by value
sorted_dict = sorted(my_dict.items(), key=lambda x: x[1])

# Print the sorted dictionary
print(sorted_dict) 

[("key1", "value1"), ("key2", "value2"), ("key3", "value3")]

To sort a dictionary by value in Python, you can use the sorted() function and pass it a lambda function that returns the value from each key-value pair.

As you can see, the dictionary has been sorted in ascending order based on the values.

Note that the sorted() function returns a list of tuples, where each tuple contains a key-value pair from the dictionary. If you want to get a dictionary back instead of a list of tuples, you can use the dict() function to convert the list of tuples to a dictionary, like this:

# Define a dictionary
my_dict = {
    "key1": "value1",
    "key2": "value2",
    "key3": "value3"
}

# Sort the dictionary by value
sorted_dict = dict(sorted(my_dict.items(), key=lambda x: x[1]))

# Print the sorted dictionary
print(sorted_dict)

{"key1": "value1", "key2": "value2", "key3": "value3"}